An example of a trait showing a non-Mendelian Inheritance pattern
The inheritance patterns seen in Mendel’s monohybrid and dihybrid crosses depend on three sets of assumptions:
In this tutorial, we will look at exceptions to assumptions (1) and (3). Exceptions to (2) will be discussed in the tutorial on sex chromosomes.
In typical dominance, only one of the two parental phenotypes is expressed in the hybrid progeny. However, in incomplete or intermediate dominance, the hybrid progeny express a third phenotype, usually intermediate between that of the two parents. For example, see the picture of the simulated cross at the left. The two pure-breeding parents are red and white. However, the F1 progeny are pink. A similar inheritance pattern is seen in carnations and sweet peas.
Crossing the hybrid progeny with each other results in an F2 progeny in which all three phenotypes are seen: red, pink, and white flowers in a ratio of 1:2:1. When intermediate dominance is involved, each genotype has a different phenotype: RR = red, Rr = pink, and rr = white.
This kind of inheritance pattern is usually interpreted as showing that a single copy of the red allele is insufficient to produce enough pigment to show dominance in the heterozygote.
A variation on incomplete dominance is seen in codominance, in which both alleles of a heterozygous pair are fully expressed. Codominance is seen in the ABO group blood type alleles described below.
Diploid organisms naturally have a maximum of 2 alleles for each gene expressing a particular characteristic, one deriving from each parent. In some cases, however, more than two types of alleles can code for a particular characteristic, as is the case of genetic coding for blood type in humans. In the ABO group, there are three alleles: A, B, and O. Usually these alleles are designated IA, IB, and i.
The reason for this elaborate representation of the genotypes is that the ABO blood group genes illustrate both multiple alleles at a locus and codominance. The A and B alleles are both dominant to the O allele, but neither A allele nor B allele is dominant to the other. Because of this combination of features, there are six possible genotypes that encode four possible blood groups: A, B, AB, and O. Because A and B are both dominant to the O type, individuals with blood type A may have two possible genotypes: IAIA or IAi. Type B individuals may similarly be either homozygous or heterozygous for the B allele. The other two blood types AB and O have unique genotypes. Type AB is genotype IA IB. Type O is the homozygote ii.
The reason for this odd pattern is that the A and B alleles both encode a sugar transferase enzyme that adds sugar to a glycoprotein in the red blood cell membrane. Each allele encodes an enzyme that adds a different sugar. The O allele, on the other hand, encodes a defective protein and adds nothing.
Both of the examples above illustrate exceptions to the monohybrid inheritance pattern. Variants to the dihybrid pattern are seen when two different gene loci each contribute to the same phenotype, e.g. feather color in budgies. Color in bird feathers depends on two things: pigment deposited in the feather and tiny ridges on the feather that produce iridescence. Budgie feathers may have yellow or no pigment from one set of gene loci, and blue or no iridescence from the presence or absence of the ridges. Various combinations of these colors produce white, yellow, green, or blue feathers. Green birds have both the pigment and the iridescence; white birds have neither. A dihybrid cross between two birds heterozygous at both loci will produce a typical 9:3:3:1 ratio, but the ratio is expressed in a single trait: feather color.
In mice, among the many gene loci that affect coat color are the albino locus and the agouti locus. To express the typical mousy gray coat color a mouse must have a normal allele at the albino locus and the normal agouti allele at the agouti locus. Mice that are homozygous for the recessive albinism gene are white. Mice that are homozygous for the recessive nonagouti gene at the agouti locus are black. Mice may, therefore, be agouti (gray), black or white. Crossing two mice that are heterozygous at both loci produces a modification of the 9:3:3:1 ratio: 9 agouti mice, 3 black mice, and 4 albinos. This is because homozygosity for the albino gene blocks expression of both the agouti and the black phenotypes.
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